Operator Precedence

Simple program for operator precedence parser in C.
It takes the expression as input and calculates the precedence of the operators.

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PROGRAM CODE:

 #include<stdio.h>  
 #include<string.h>  
 void main()  
 {  
   int i,j,cnt=1;  
   char operators[] ="*/%+-",input[100];  
   printf("Enter the statement : ");  
   gets(input);  
   for(i=0;i<strlen(operators);i++)  
   {  
     for(j=0;j<strlen(input);j++)  
     {  
       if(input[j]==operators[i])  
       {  
         printf("%d %c=%c%c%c\n",cnt++,input[j-1],input[j-1],input[j],input[j+1]);  
         input[j+1]=input[j-1];  
       }  
     }  
   }  
 }  

OUTPUT:

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