April 18, 2015
GRK
Problem Statement
You’re given the pointer to the head node of a linked list and you need to print all its elements in order, one element per line. The head pointer may be null, i.e., it may be an empty list. In that case, don’t print anything!
Source code:
/*
Print elements of a linked list on console
head pointer input could be NULL as well for empty list
Node is defined as
struct Node
{
int data;
struct Node *next;
}
*/
void Print(Node *head)
{
// This is a "method-only" submission.
// You only need to complete this method.
while(head!=NULL){
cout<<head->data<<endl;
head = head->next;
}
}
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