April 18, 2015
GRK
Problem Statement
You’re given the pointer to the head node of a doubly linked list. Reverse the order of the nodes in the list. The head node might be NULL to indicate that the list is empty.
Source Code:
/*
Reverse a doubly linked list, input list may also be empty
Node is defined as
struct Node
{
int data;
Node *next;
Node *prev;
}
*/
Node* Reverse(Node* head)
{
Node *cur = head,*temp = new Node;
// Complete this function
// Do not write the main method.
while(cur !=NULL){
temp->next = cur->next;
temp->prev = cur->prev;
cur->next = temp->prev;
cur->prev = temp->next;
cur = temp->next;
if(cur!=NULL){
head = cur;
}
}
return head;
}
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