# Hackerrank Reverse a doubly linked list solution

## Problem Statement

This challenge is part of a tutorial track by MyCodeSchool

You’re given the pointer to the head node of a doubly linked list. Reverse the order of the nodes in the list. The head node might be NULL to indicate that the list is empty.

## Source Code:

/*
Reverse a doubly linked list, input list may also be empty
Node is defined as
struct Node
{
int data;
Node *next;
Node *prev;
}
*/
{
Node *cur = head,*temp = new Node;
// Complete this function
// Do not write the main method.
while(cur !=NULL){
temp->next = cur->next;
temp->prev = cur->prev;
cur->next = temp->prev;
cur->prev = temp->next;
cur = temp->next;
if(cur!=NULL){
}
}
}
** The above solution is my own code and it may not be the optimal solution or optimal way to approach the problem but it passes all the testcases in Hackerrank. So if you have any optimal approaches feel free to paste the code as the comment below..... :) :) :)

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